Class 7 Maths Group- Comment on this post to share how you solved the problem. Remember to talk about the strategy you used not just the answer.
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On Number 2 I solved the problem by going by 10-5.40 and her change was 4.60 and that is how i got the anwser.
ReplyDeleteProblem 1
ReplyDeleteI had 5 dollars and took away 1.10 cents and then I had $ 3.00 and 90 cents left. That's how I got 3 dollars 90.
Hi Mrs J
ReplyDeletehere is my working out so I did $10 - 4.60 then I did (4-6)+(0.4 - 0.6)=0.06
then it =5.40 thanks bye :3
Hi Mrs Jacobsen This is my problem that I solved
ReplyDelete1.10 - $2 = 90 cents
2-1=$1
$1- 10 cents= 90 cents
So The Answer is 90 cents
I am going work number 2 first $10 - $4 =$6 and then 6$-60c= 5$.40c
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteHi Mrs J
ReplyDeleteFor Number I did
10-4=6-60 cents=5.40
Thanks and Bye
1. $2.00 - $1.10 = [ ]
ReplyDeleteI know that $2.00 - $1.00 is $1.00
And I know that $1.00 + 10 c = $1.10 is the answer
Problem 2
ReplyDeleteI had $10 I get $4.60 change and then I take $4 away from the ten and that make $6 then I break up a dollar into 60c and 40c so the answer is $5.40
Problem 2.
ReplyDeleteI did $10 - $4 = $6
I took away $1.60 and that = $5.40
2, $10 - $4.60 ?
ReplyDeleteI know that $10 - $4 =$6
and I know that $6 - 60 = 5.40 so the answer is 5.40
Problem 1
ReplyDeleteI had 5 and took away 1 so I had $4. Then I took $1 and broke it into 10c and 90c. I had $4-$1=$3 and 90cents so it was $3.90.
Problem 1.
ReplyDeleteI know if I have 5 and I take away 1 I will have $4. Then I split $1 into 90c and 10c, then I do
$4-$1=$3 so $3+90c=$3.90c